When factoring polynomials, the first step is always to look for common factors and to factor them out. After that, you can see if the polynomial can be factored further.

You are watching: Which of the following is a requirement for a trinomial to be factored as a perfect square?

There is a special situation called the difference of two squares that has a special pattern for factoring.Here is the pattern:
*
First, notice that there are three requirements that must be met in order for us to be able to use this pattern.
1)It must be a binomial (have two terms)2)Both terms must be perfect squares (meaning that you could take the square root and they would come out evenly.)3)There must be a subtraction/negative sign (not addition) in between them
If these three requirements are met, then we can easily factor the binomial using the pattern. Simply...
1)Write two parenthesis2)Put a
*
in one and a
*
in the othe3)Take the square root of the first term and put that in the front of each parenthesis4)Take the square root of the last term and put that in the back of each parenthesis
As before, you can check your work by multiplying out your answer and making sure the result matches the original.
1)
*
First check for common factors - there are none, so we can
continue on to check the criteria. It is a binomial with two perfect squares and subtraction, so we can use this pattern.
We set up two parenthesis with a+ in one and a- in the other We take the square root of x2,which is x, and put that in the
front of each parenthesis. We take the square root of 25 which is 5 and put that in the back of each.

See more: What Is The Role Of Cmos In Modern Computer, What Is The Relationship Between Bios And Cmos


Final answer: . We can check this by multiplying it out (remember to
distribute or use FOIL). We get
*
. This matches the original, so we know we factored correctly.
2)
*
First check for common factors – there are none, so we can
We set up two parenthesis with a+ in one and a- in the other
*
We take the square root of
*
, which is
*
, and put that